why I can't use "linalg::substitute" in R2013a?

if true 
>>aaas=zeros(20,2);
>>aaaf=rand(10,2);
>> linalg::substitute(aaas,aaaf,1,1)
end

It tells me "Error: Unexpected MATLAB operator."

Answer 1

[Sean de Wolski]

linalg::substitute(aaas,aaaf,1,1)

Is a MuPAD command. You'll have to run it from within MuPAD. To Open MuPAD, either run the App from the Apps tab or run:

>>mupad

for more information on it:

doc mupad

[yang]

Thanks for fast response. Is there a regular command with the same function?