how can I Compute the value of d for the following values of x , Outcome equation d=((34.63/x)-5.126)/2.54

Is my code right i am beginner in matlab.

>>clc

>>clear

for x=[0.1000,0.1500,0.2000]

fprintf("\n\t%g\n",x)

else d=((34.63/x)-5.126)/2.54

disp ("ANSWER")

end

"OUTCOME WANTED RESULT "

Answer 1

[DGM]

I have no idea what that code is intended to do, but if you just want to evaluate the expression all x:

x=[0.1000,0.1500,0.2000]
d=((34.63./x)-5.126)/2.54

I guess if you're trying to get it to display formatted results to console, you could do that as well.

for l=1:numel(x)
	fprintf('\t%g\t%g\n',x(l),d(l))
end

[Hamada Alkhlif]

i want to Write a code or script including a FOR LOOP in order to computing the value of d for the following values of x and returning an output variable named ANSWER just as shown : x = 0.10, x = 0.15, and x = 0.20

[DGM]

you mean like this?

x=[0.1000,0.1500,0.2000];
d=((34.63./x)-5.126)/2.54;
answer=[x' d']

[Hamada Alkhlif]

yes

[Hamada Alkhlif]

thanks alot DGM

[Hamada Alkhlif]

so i believe the code as we put the for loop in it it becomes like this

x=[0.1000,0.1500,0.2000];

d=((34.63./x)-5.126)/2.54;

for l=1:numel(x)

fprintf('\t%g\t%g\n',x(l),d(l))

answer=[x' d']

end

is it @DGM ?

[Hamada Alkhlif]

actually iam getting the answer right but it look deferent .

answer after submitte above code :

>> Untitled3

0.1 134.32

answer =

0.1000 134.3205

0.1500 88.8743

0.2000 66.1512

0.15 88.8743

answer =

0.1000 134.3205

0.1500 88.8743

0.2000 66.1512

0.2 66.1512

answer =

0.1000 134.3205

0.1500 88.8743

0.2000 66.1512

>>

i just want the code to give 1 answer like this

answer =

0.1000 134.3205

0.1500 88.8743

0.2000 66.1512

how can i modify the last code @DGM ?

[Steven Lord]

Every time this line of code executes:

answer=[x' d']

it assigns a value to the variable named answer then displays the contents of that variable. If you just want to assign a value to the variable but not display it, end the line of code with a semicolon.

answer=[x' d'];

Then if you want to display it at the end of the code you can.

disp(answer) % or just plain
answer

Answer 2

[VBBV]

   %true
d = [];
for x=[0.1000,0.1500,0.2000]
d=[d ((34.63/x)-5.126)/2.54];
disp ("ANSWER");
end
x=[0.1000 0.1500 0.2000];
fprintf("\t%4g\t\t%4g\n",[x;d])

[Hamada Alkhlif]

this is almost the wanted code just is that the x values not in 4 decimals and it the code out put display 3 words of answers ,it required only one .

[VBBV]

d = [];
for x=[0.1000,0.1500,0.2000]
d=[d ((34.63/x)-5.126)/2.54];
end;
disp ("ANSWER");
x=[0.1000 0.1500 0.2000];
fprintf("\t%.4f\t\t%.4f\n",[x;d])

Try this