how to make nxn matrix

31 Ansichten (letzte 30 Tage)
WonJong We
WonJong We am 14 Apr. 2021
Kommentiert: WonJong We am 15 Apr. 2021
I want to make nxn matrix by follweing rule
n=input
first and last is 1
how can do it?
This is the original formula.
clc;
n=input
A=(n ; n)???
  2 Kommentare
Walter Roberson
Walter Roberson am 14 Apr. 2021
Sorry, that image is too faint to read.
WonJong We
WonJong We am 14 Apr. 2021
Thank you for the information.
I will change!!

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 14 Apr. 2021
n = 7
n = 7
d = ones(1,n-2)/2;
M = zeros(n,n) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 7×7
1.0000 0 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0 1.0000
  9 Kommentare
Walter Roberson
Walter Roberson am 15 Apr. 2021
n=3;
%n=input ('put your n=')
d = ones(1,n-1)/2;
M = zeros(n+1,n+1) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 4×4
1.0000 0 0 0 0.5000 0 0.5000 0 0 0.5000 0 0.5000 0 0 0 1.0000
T = [sym('T0') ; sym('T',[n 1]) ]
T = 
Tvals = T;
Tvals(1) = 500;
Tvals(n+1) = 300; %Tn is at position n+1
MT = subs(M*T, T, Tvals)
MT = 
eqn = MT == T
eqn = 
sol = solve(eqn)
sol = struct with fields:
T0: [1×1 sym] T1: [1×1 sym] T2: [1×1 sym] T3: [1×1 sym]
sol.T0
ans = 
500
sol.T1
ans = 
sol.T2
ans = 
sol.T3
ans = 
300
WonJong We
WonJong We am 15 Apr. 2021
Thank you!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by