Transform 3D binary matrix into 2D

Dear colleagues,

I would like to kindly ask you for the help with the transformation from 3D into 2D matrix. Supposing that I have stored the binary image in the variable seg1, containing 45 layers (seg1(:,:,45)). I need to make the 2D matrix with the same dimension(rows and columns) as seg1 with keeping the same pixel values: original=1, result=1 and original=0, result=0. Here is my code, but it does not work well. Thank you very much for your help.

[row col lev]=size(seg1);
 
seg2=zeros(row,col);
 
for i=1:lev
for j=1:row
         for k=1:col
           
if seg1(j,k,i)=1
    seg2(j,k)=1;
else 
   seg2(j,k)=0;
   end
 end
         end
end

Answer 1

[Jan]

Your code overwrites the output for each loop over i=1:lev. An equivalent code without a loop:

%seg2 = seg1(:, :, end);

What should happen with the 45 bits of the input? Do you want to store them as bits of integer values?

seg1 = randi([0,1], 3,4,5);
[row, col, lev] = size(seg1);
tmp  = reshape(seg1, row*col, lev) * pow2(lev-1:-1:0).';
seg2 = reshape(tmp, row, col);