Error plotting fzero function - "Operands to the || and && operators must be convertible to logical scalar values"
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Saumya Nagar 17BME0447
am 7 Apr. 2021
Kommentiert: DGM
am 9 Apr. 2021
Good Day!
I am trying to plot the solution of an equation using fzero function but getting the error - "Operands to the || and && operators must be convertible to logical scalar values". Can anyone please help me out.
The code is
clc;
clear all;
format short;
Throat_Diameter=2.8;
Exit_Diameter=5.76;
G=1.4;
Throat_Area=3.14159265.*(10.^(-6)).*((Throat_Diameter).^2)/4;
Exit_Area_inMeter=3.14159265.*(10.^(-6)).*((Exit_Diameter).^2)/4;
Diverging_Length= input('Enter the length of diverging section in mm: )' );
Distance_from_throat=linspace(1,Diverging_Length,50);
Section_Diameter=Throat_Diameter+((Exit_Diameter-Throat_Diameter)*Distance_from_throat)/Diverging_Length;
Section_Area=3.14159265.*(10.^(-6)).*((Section_Diameter).^2)/4;
ARatio=Section_Area/Throat_Area;
problem.objective = @(M) (1/M.^2).*(((2+(G-1).*M.^2)/(G+1)).^((G+1)/(G-1)))-ARatio.^2; % Objective function
problem.solver = 'fzero'; % Find the zero
problem.options = optimset(@fzero); % Default options
% Solve supersonic root
problem.x0 = [1+1e-6 50]; % Supersonic solver bounds
M_Local = fzero(problem); % Solve for supersonic M
plot(Distance_from_throat,M_Local)
The error is:
Operands to the || and && operators must be convertible to logical scalar values.
Error in fzero (line 421)
while fb ~= 0 && a ~= b
Error in PlottingAreaMachRelation (line 23)
M_Local = fzero(problem); % Solve for supersonic M
0 Kommentare
Akzeptierte Antwort
DGM
am 7 Apr. 2021
Bearbeitet: DGM
am 7 Apr. 2021
You've set Distance_from_throat to a vector. As far as I know, fzero() handles scalars only. You can always find all the solutions with a simple loop.
clc; clf
clear all;
format short;
Throat_Diameter=2.8;
Exit_Diameter=5.76;
G=1.4;
Throat_Area=3.14159265.*(10.^(-6)).*((Throat_Diameter).^2)/4;
Exit_Area_inMeter=3.14159265.*(10.^(-6)).*((Exit_Diameter).^2)/4;
Diverging_Length= 5;%input('Enter the length of diverging section in mm: )' );
DFT=linspace(1,Diverging_Length,50);
M_Local=zeros([1 numel(DFT)]);
for d=1:numel(DFT)
Distance_from_throat=DFT(d);
Section_Diameter=Throat_Diameter+((Exit_Diameter-Throat_Diameter)*Distance_from_throat)/Diverging_Length;
Section_Area=3.14159265.*(10.^(-6)).*((Section_Diameter).^2)/4;
ARatio=Section_Area/Throat_Area;
problem.objective = @(M) (1/M.^2).*(((2+(G-1).*M.^2)/(G+1)).^((G+1)/(G-1)))-ARatio.^2; % Objective function
problem.solver = 'fzero'; % Find the zero
problem.options = optimset(@fzero); % Default options
% Solve supersonic root
problem.x0 = [1+1e-6 50]; % Supersonic solver bounds
M_Local(d) = fzero(problem); % Solve for supersonic M
end
plot(DFT,M_Local)
2 Kommentare
DGM
am 9 Apr. 2021
The simple way would be to add another loop. If we arrange the y-series as rows in the output matrix, we can plot them all at once.
Throat_Diameter=2.8;
Exit_Diameter=5.76;
G=[1.2 1.4 1.6];
Throat_Area=3.14159265.*(10.^(-6)).*((Throat_Diameter).^2)/4;
Exit_Area_inMeter=3.14159265.*(10.^(-6)).*((Exit_Diameter).^2)/4;
Diverging_Length= 5;%input('Enter the length of diverging section in mm: )' );
DFT=linspace(1,Diverging_Length,10);
M_Local=zeros([numel(G) numel(DFT)]);
for g=1:numel(G)
for d=1:numel(DFT)
Distance_from_throat=DFT(d);
Section_Diameter=Throat_Diameter+((Exit_Diameter-Throat_Diameter)*Distance_from_throat)/Diverging_Length;
Section_Area=3.14159265.*(10.^(-6)).*((Section_Diameter).^2)/4;
ARatio=Section_Area/Throat_Area;
problem.objective = @(M) (1/M.^2).*(((2+(G(g)-1).*M.^2)/(G(g)+1)).^((G(g)+1)/(G(g)-1)))-ARatio.^2; % Objective function
problem.solver = 'fzero'; % Find the zero
problem.options = optimset(@fzero); % Default options
% Solve supersonic root
problem.x0 = [1+1e-6 50]; % Supersonic solver bounds
M_Local(g,d) = fzero(problem); % Solve for supersonic M
end
end
h=plot(DFT,M_Local); grid on
aa=num2cell(G);
tagfun=@(x) sprintf('G = %2.2f',x);
legend(h,cellfun(tagfun,aa,'UniformOutput',false),'location','northwest')

Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Specifying Target for Graphics Output finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!