Numerical Output from a Symbolic Expression
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Ammar Taha
am 4 Apr. 2021
Kommentiert: Star Strider
am 4 Apr. 2021
I'm coding the Newton method for root finding using function handles and symbolic expression to determine the derevative of f(x), the output after four iteration is : 665857/470832, which is a correct answer but not formatted the right way. I understand that this is due to the subs function, but I really don't know what is happening in the background.
For reference I got the right format by using >>vpa(ans,5);
So why Matlab is doing that?!
0 Kommentare
Akzeptierte Antwort
Star Strider
am 4 Apr. 2021
‘So why Matlab is doing that?!’
Because the results of symbolic expressions and operations remain symbolilc.
Another option would be:
double(ans)
if you want to use the result in numerical calculations outside of the symbolic environment.
2 Kommentare
Weitere Antworten (1)
Walter Roberson
am 4 Apr. 2021
Bearbeitet: Walter Roberson
am 4 Apr. 2021
sympref('floatingpointoutput', true)
As to "why":
When you use a double precision value in a symbolic expression, the Symbolic Toolbox processes the double precision number with sym() to convert it to symbolic number. The default conversion is processing with the 'r' (rational) conversion, which creates rational numbers (unless it can find a simple square root or multiple of pi)
You can force individual double precision numbers to be processed differently by calling sym() yourself with one of the other conversion flags.
However... what you should probably be doing instead is taking the symbolic expression of your function and its derivative and using matlabFunction() to convert them into double precision functions, and then this would no longer be relevant.
0 Kommentare
Siehe auch
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!