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Shortest path constrained to use specific nodes

3 Ansichten (letzte 30 Tage)
Tejas
Tejas am 3 Apr. 2021
Bearbeitet: Matt J am 3 Apr. 2021
Let's say I have a simple graph:
G = graph([1,2,3,4,5],[2,3,4,5,1]);
I want to find the shortest path from 1 to 3. The shortestpath function would give me 1-2-3. But in my case, I have a list of nodes that I can travel on:
nodes = [1,3,4,5];
How can I find the shortest path between any two nodes in the graph that only takes the nodes in that list (which will be 1-5-4-3 in this case)?

Antworten (3)

Matt J
Matt J am 3 Apr. 2021
Bearbeitet: Matt J am 3 Apr. 2021
Why not just analyze a subgraph with the inadmissible nodes removed:
cut=setdiff(1:numnodes(G),nodes);
Gsub=rmnodes(G,cut);

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 3 Apr. 2021
Here is an easy solution:
shortestpath(G, 1,3) % Shortest path between 1 and 3
Good luck.
  1 Kommentar
Tejas
Tejas am 3 Apr. 2021
That does not answer my question, since it'll give 1-2-3, and I cannot use 2.

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Tejas
Tejas am 3 Apr. 2021
Okay, I realised if I assign weights like:
G = graph([1,2,3,4,5],[2,3,4,5,1],[Inf,1,1,1,1]);
Then I do get
shortestpath(G,1,3)
ans =
1 5 4 3
I don't have any other purpose for weights so I can use them in this way.

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