Solving a simple equation
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Richard Golem
am 2 Apr. 2021
Kommentiert: Paul Hoffrichter
am 5 Apr. 2021
%Angle = B
%Thickness = u
%Inner Radius = p
%Developed length = L
%L = L1+L2+a
%Bend Allowance = a
B = 90;
u = .075;
p = .046875;
L1 = 12;
L2 = 3.5;
syms B u p v;
v = solve(v == pi*((180-B)/180)*(p+(u/2e-6)*(6.5e-6+5e-6*log(p/u)))-2e-6*(p+u),v);
%syms v L1 L2 L;
%L = solve(L==L1+L2+v);
disp(v)
%I am trying to ultimatly solve for L, however when I try and solve for v it comes out wit a really long and complicated equation that includes my variables. I put the equation with the right number in my calculator and got a single number using the same notation, so I'm pretty sure the problem is somewhere in my code. It is probalby really obvius, but I am pretty new and don't know what I'm doing wrong. Any help would be great, thank you.
0 Kommentare
Akzeptierte Antwort
Paul Hoffrichter
am 2 Apr. 2021
Sorry, no idea if this is right.
clc, clearvars
%Angle = B
%Thickness = u
%Inner Radius = p
%Developed length = L
%L = L1+L2+a
%Bend Allowance = a
B = 90;
u = .075;
p = .046875;
L1 = 12;
L2 = 3.5;
% % % syms B u p v;
syms v
v = solve(v == pi*((180-B)/180)*(p+(u/2e-6)*(6.5e-6+5e-6*log(p/u)))-2e-6*(p+u),v);
%syms v L1 L2 L;
%L = solve(L==L1+L2+v);
disp(v)
val = double(v);
disp(val);
Output:
1432527233130751/4503599627370496
0.318084943524866
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Assumptions finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!