How to change data in a cell array of doubles?
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Graduate Student
am 31 Mär. 2021
Kommentiert: Mirthand
am 1 Apr. 2021
I have attached the variable that I am trying to change. The first column in each double is time. I would like to go through all the trials and fix the time so that it starts from 0, by doing time = time - 1
Time for the first trial (portion).
9.69938400000000
9.74050100000000
9.75054700000000
9.75911600000000
9.76805000000000
9.78226300000000
9.83225600000000
9.86755800000000
9.88683400000000
9.89537800000000
9.90186700000000
9.90746900000000
9.91257600000000
0 Kommentare
Akzeptierte Antwort
per isakson
am 31 Mär. 2021
??? "doing time = time - 1" doesn't "fix the time so that it starts from 0"
Try this
>> load('trials.mat')
>> cac = cellfun( @(num) num-[num(1,1),0,0,0,0,0,0], trials, 'uni',false );
>> trials{1}(1:6,:)
ans =
9.6994 0 2673.3 0 4.93 0.41 600
9.7405 0 2673.7 0 10 0.41 600
9.7505 0 2674.1 0 40.91 0.82 600
9.7591 0 2674.5 0 47.96 1.23 600
9.7681 0 2674.9 0 46 1.64 600
9.7823 0 2675.3 0 28.91 2.05 600
>> cac{1}(1:6,:)
ans =
0 0 2673.3 0 4.93 0.41 600
0.041117 0 2673.7 0 10 0.41 600
0.051163 0 2674.1 0 40.91 0.82 600
0.059732 0 2674.5 0 47.96 1.23 600
0.068666 0 2674.9 0 46 1.64 600
0.082879 0 2675.3 0 28.91 2.05 600
>>
Or "doing time = time - 1"
>> cac = cellfun( @(num) num-[1,0,0,0,0,0,0], trials, 'uni',false );
5 Kommentare
per isakson
am 1 Apr. 2021
I don't know how to answer.
MATLAB Onramp ...Learn the essentials of MATLAB through this free, two-hour introductory tutorial on commonly used features and workflows....
Do some experiments, e.g.
>> m = magic(3)
m =
8 1 6
3 5 7
4 9 2
>> m - [m(1,1),0,0]
ans =
0 1 6
-5 5 7
-4 9 2
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Cell Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!