solve() is unable to find a solution

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SOURAV KUMAR
SOURAV KUMAR am 26 Mär. 2021
Kommentiert: Alan Stevens am 14 Apr. 2021
Hello everyone,
I was trying to solve a transcendental eqation in MATLAB
I performed two programs one graphical approach and another by solve()
In the graphical approach, I find one solution exists in the range () for , as shown in the figure below
i.e., the intersection of blue and red curve ()
Now, when i performed another program (T2.m) using solve() :
Command Prompt is giving empty sym with the following message:
Warning: 3 equations in 1 variables.
> In C:\Program Files\MATLAB\R2013a\toolbox\symbolic\symbolic\symengine.p>symengine at 56
In mupadengine.mupadengine>mupadengine.evalin at 97
In mupadengine.mupadengine>mupadengine.feval at 150
In solve at 170
In T2 at 16
Warning: Explicit solution could not be found.
> In solve at 179
In T2 at 16
k1_sol = [ empty sym ]
My T2.m is as follows:
clc
clear all
close all
one_eV= 1.6/(10^19);
Vo=0.3 * one_eV;
b=5/(10^9);
S=Vo*b;
a=10/(10^9);
m=0.067 * 9.1/(10^31);
h=6.626/(10^34);
hbar= h/(2*pi);
k=pi/(4*a);
lhs= cos(k*a);
syms k1
rhs=cos(k1*a) + (m*S)*sin(k1*a)/(hbar^2 * k1);
k1_sol= solve(lhs== rhs,k1 >= 0.27*(10^9), k1 <= 0.32*(10^9))
so, how to rectify this?

Akzeptierte Antwort

Alan Stevens
Alan Stevens am 26 Mär. 2021
Just solve it numerically using fzero. Take the initial guess close to the average value of the bounds you specify:
k1_0 = 0.29E9; % initial guess
k1 = fzero(@k1fn,k1_0);
disp(k1)
disp(cos(pi/4)) % = cos(k*a)
function Z = k1fn(k1)
one_eV= 1.6/(10^19);
Vo=0.3 * one_eV;
b=5/(10^9);
S=Vo*b;
a=10/(10^9);
m=0.067 * 9.1/(10^31);
h=6.626/(10^34);
hbar= h/(2*pi);
k=pi/(4*a);
Z = cos(k1*a) + (m*S)*sin(k1*a)/(hbar^2 * k1) - cos(k*a);
end
this reults in
2.7859e+08 for k1 and 0.7071 for left and right hand sides of your equation.
  2 Kommentare
SOURAV KUMAR
SOURAV KUMAR am 14 Apr. 2021
@Alan Stevens can you please tell me why solve() is not able to find the solution?
Alan Stevens
Alan Stevens am 14 Apr. 2021
I don't know!

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