Find row number of elements
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Hi, I have a list of branches, BL, and a list of nodes, nodeList.
BL has two columns, containing to-from nodes for each branch. All elements in nodeList are included at least once in BL.
I want to create a list of branches that are connected to one or more nodes in nodeList.
What I want to achieve:
BL =
1 2
1 3
2 4
3 4
4 5
5 6
nodeList =
1
3
tempBranch =
1
2
4
The way I'm doing it now (below) is very ineffective, so I'm hoping someone knows a better way to do this.
Can I do this without loops?
for j = 1:rows %%rows in BL
if BL(j,1) == nodeList(i) || BL(j,2) == nodeList(i)
tempBranch(k) = j;
k = k + 1;
end
end
Thanks!
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Akzeptierte Antwort
Azzi Abdelmalek
am 1 Jun. 2013
Bearbeitet: Azzi Abdelmalek
am 1 Jun. 2013
tempBranch =find(any(ismember(BL,nodeList),2))
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