# How can I calculate and compare the energy of the curvelet coefficients to compare in thresholding code?

5 Ansichten (letzte 30 Tage)
ahmet am 31 Mai 2013
Kommentiert: Ranadev Singha am 3 Mär. 2014
I am working on image compression with Curvelet Transform. I already have the coefficient matrix cell as C={1,2}(k,l)..I would like to corp the unnecessary coefficients from this matrix but I don't know how to decide which ones should be removed or trimmed.
##### 1 KommentarKeine anzeigenKeine ausblenden
Ranadev Singha am 3 Mär. 2014
Hello,Ahmet i am also pursuing a project on curvelet transform for a data set in the form of a matrix.But i have a problem regarding finding out the coefficients of the transform. i have used many codes but in vain. Could you please send me the code which you have used for getting the coefficients. Waiting for your reply. please try to send me the code which you have used . it wud be of great help Thanking you Regards Ranadev Singha

Melden Sie sich an, um zu kommentieren.

### Akzeptierte Antwort

Kye Taylor am 31 Mai 2013
When you decompose a function f in an orthonormal basis, you can relate the sum of the square of the coefficients to the L2-norm (read energy) of the function via Parseval's identity. To get the best approximation in a lossy compression, you want to kill the coefficients that are smallest when squared.
The number of coefficients you decide to threshold depends on the amount of compression your looking for and the quality of the reconstruction: As you threshold more coefficients, you will degrade the quality of the reconstruction.
Now, using curvelets is another story since a curvelet transform is highly redundant (not orthogonal). With that said, you could still proceed by killing those coefficients that are "small enough," and just monitor the quality of the recongstruction as you do..
##### 2 Kommentare1 älteren Kommentar anzeigen1 älteren Kommentar ausblenden
Kye Taylor am 31 Mai 2013
I interpret your prof's suggestion in this way: You could look at the distrubtion of the squared-magnitude of each coefficient. For example
t = linspace(0,2*pi,512);
x = exp(t) + 0.1*randn(size(t));
y = fft(x-mean(x));
hist(abs(y),25);
Notice from the histogram, there are a lot of very small coefficients. So, you would not want to start thresholding at the average magnitude (since this would kill all the small coefficients). Instead, start killing only the smallest:
% vector of values to threshold
th = linspace(min(abs(y)),max(abs(y)),16);
figure
for i = 1:length(th)
subplot(4,4,i)
hold on
y(y<th(i)) = 0; % threshold values small enough
xrecon = ifft(y);
plot(x-mean(x),'b')
plot(xrecon,'r')
title([num2str(nnz(y)),' coefficients used.'])
end

Melden Sie sich an, um zu kommentieren.

### Kategorien

Mehr zu Signal Analysis finden Sie in Help Center und File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by