using FIND in 3D matrix

I am trying to find the 3rd dimension index value for the following case

A(:,:,1)=[1 2 ; 3 4]
A(:,:,2)=[9 8 ; 4 4]
A(:,:,3)=[2 4 ; 7 4]

B=[1 2 ; 3 4]

How can I use find(.) for this purpose

Answer 1

[Azzi Abdelmalek]

idx=find(arrayfun(@(x) isequal(A(:,:,x),B),1:size(A,3)))

Answer 2

[Sean de Wolski]

I would do that like this:

A(:,:,1)=[1 2 ; 3 4];
A(:,:,2)=[9 8 ; 4 4]; 
A(:,:,3)=[2 4 ; 7 4];
A(:,:,4)=A(:,:,1);

B=[1 2 ; 3 4];

idx = find(all(all(bsxfun(@eq,A,B),1),2))

Find where all elements in rows/cols are equal in pages

[xplore29]

I didnt understand why would you declare A(:,:,4)=A(:,:,1).

[Azzi Abdelmalek]

It's just an example to test the code

Answer 3

[Andrei Bobrov]

[ii,jj]=ismember(reshape(A,[],size(A,3))',B(:)','rows');
out = jj(ii);