problem with symbolic calculation
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
YOGESHWARI PATEL
am 14 Mär. 2021
Kommentiert: YOGESHWARI PATEL
am 17 Mär. 2021
I want symbolic calculation .I write the code but error is displayed
syms a
syms R
n=input('enter the value of n')
F(1)=1;
F(2)=0;
F(3)= a;
aplha=input('enter the value of a=')
R=input('enter the value of reynold number R=')
for i=1:n
F(i+3)=2*alpha*R*F(i)+F(i+1);
end
0 Kommentare
Akzeptierte Antwort
Walter Roberson
am 16 Mär. 2021
Bearbeitet: Walter Roberson
am 16 Mär. 2021
aplha=input('enter the value of a=')
You assign to aplha . A. P. L. H. A
R=input('enter the value of reynold number R=')
for i=1:n
F(i+3)=2*alpha*R*F(i)+F(i+1);
You use alpha . A. L. P. H. A.
You have not assigned to alpha.
alpha happens to exist as a function, but the function alpha requires that you pass a parameter to it, so you would get an error.
You need to change your input() to assign to alpha instead of aplha
Weitere Antworten (1)
Steven Lord
am 14 Mär. 2021
The way you've written it, when you try to assign a into F(3) MATLAB needs to convert the symbolic a into a numeric value so it can be stored in the numeric array F. But what is the numeric value of a? It doesn't have one, which is why MATLAB complains.
Since you want F to be able to store symbolic variables, don't initialize it to be a numeric array first. Initialize it as symbolic from the start by assigning a symbolic expression to it to create the array.
F(1) = sym(1);
Or since you know how large it will need to be in the end:
F = sym(zeros(1, n+3));
Siehe auch
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!