Replacing numbers in a matrix
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I am trying to create a command that replaces all even numbers in a matrix with their square root values. I've already figured out how to determine which numbers are even. Please help.
function repEven = repEven(A)
if rem(A,2) == 0 % determines if numbers are even
end
Antworten (1)
Walter Roberson
am 13 Mär. 2021
Bearbeitet: Walter Roberson
am 13 Mär. 2021
Use logical indexing.
if rem(A,2) == 0 % determines if numbers are even
That determines whether all of the numbers in A are even, not if any one of them is even.
Also, do not name your output variable the same thing as your function.
3 Kommentare
Ryan Williams
am 13 Mär. 2021
A = [5 8 19]
rem(A,2) == 0
is a logical vector of true and false values.
A([false, true, false])
Ryan Williams
am 13 Mär. 2021
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