Replace character in string/cell with the character above it
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Dora de Jong
am 11 Mär. 2021
Kommentiert: Dora de Jong
am 11 Mär. 2021
String/cell example: --> real string/cell is very long
a= { 'a' ; 'b' ; 'c' ; 'b'}
Wanted outcome:
a_new= { 'a' ; 'a' ; 'c' ; 'c'}
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the cyclist
am 11 Mär. 2021
Bearbeitet: the cyclist
am 11 Mär. 2021
The general rule is not perfectly clear to me, from your small example. Do you mean that you want the even-numbered elements to be replaced? If so, then
anew = a;
a(2:2:end) = a(1:2:end-1);
If not, maybe you could explain in a little more detail.
3 Kommentare
the cyclist
am 11 Mär. 2021
Bearbeitet: the cyclist
am 11 Mär. 2021
Here is one way:
a = { 'a' ; 'b' ; 'c' ; 'b' ; 'h' ; 'g' ; 'b'};
replace_idx = find(strcmp(a,'b'));
a_new = a;
a_new(replace_idx) = a_new(replace_idx-1);
This will not work if 'b' is the first element, so you will need to modify this algorithm in that case. But you haven't given info on what you want to do then.
Weitere Antworten (1)
Jan
am 11 Mär. 2021
Bearbeitet: Jan
am 11 Mär. 2021
Maybe:
a_new = a;
a_new(2:2:end) = a(1:2:end);
Or:
index = repelemt(1:2:numel(a), 1, 2):
a_new = a(index)
[EDITED] after your comment: "So every b wil be replaced with the character above it"
index = find(strcmp(a, 'b'));
a(index) = a(index - 1);
What about: {'a'; 'b'; 'b'} or {'b'} or {'b', 'a'}?
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