For loop with previous result

for t=1:n
    a(t)=600+10^t
    b(t)=600-a(t)
end

I want that b to always taking the previous result

so, b(1)=600-a(1)

b(2)=(600-a(1))-a(2)

b(3)=(600-a(1)-a(2))-a(3)

how can i change the t

Answer 1

[Mathieu NOE]

hello Jane

this is it :

at the k step : b(k) is 600 - sum of a from 1 to k

for t=1:n
    a(t)=600+10^t;
    b(t)=600-sum(a(1:t));
end

[Jane Smith]

worked thank you!