Reshape list into columns
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Joel Schelander
am 2 Mär. 2021
Beantwortet: Gargi Patil
am 15 Apr. 2021
Im working with driving data for vehicles. There is 429 vehicles (DeviceStats). For the trips, there is a list of 107910 rows with one value per row (Car). The value is the id number of the vehicles. The format of the list looks like this
173
173
173
178
178
184
and so on. Every vehicle has a different number of vehicles in the Car vector. I want to reshape the list to 429 columns, where each column has the length the same length as the vehicle has in the Car-list. Like this
173 178 184
173 178
173..
My approach so far has not worked:
clc
clear
load EXJOBB
D=[];
Car=tripStats.device;
Devicestats=deviceStats.device;
for j=1:429
for i=1:107910
if Car(i)==Devicestats(j)
D(i,j)=[Car(i)];
else
break
end
end
end
3 Kommentare
Stephen23
am 2 Mär. 2021
Matrices must be rectangular, i.e. all rows have the same number of columns, all columns have the same number of rows.
Gaps, missing data, holes, rows or columns of different lengths are not supported.
Do you want to:
- pad the columns with some default value, e.g. 0, NaN, etc. (if so, what value?)
- use a container array (e.g. cell array) to hold numeric vectors of different lengths?
Akzeptierte Antwort
Gargi Patil
am 15 Apr. 2021
I understand that you would like to create a matrix with each column containing same elements and each row having unique elements.
You have asked a similar question here which has been answered:
To extend the above solution further:
list = [173 173 173 178 178 184];
%Get unique elements in list
uniqueEle=unique(list(:,1));
num = numel(uniqueEle);
res = zeros(num,num);
ii = 1;
for i = 1:numel(uniqueEle)
output = list(list(:,1)==uniqueEle(i),:);
%Append zeros to make output of length num
output((end+1):num,1)=0;
res(:, ii) = output;
ii = ii + 1;
end
res will return the desired output matrix.
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