accessing surrounding elements in an array
8 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi
I'm currently a complete newbie to MATLAB and I'm having trouble with a few things. I have several png files and I've counted the number of pixels that are above a certain input. I want to smooth the image/data by accessing each in the array and averaging it with its surrounding elements, excluding the boundaries of the image.
I know how to access each individual element in an array using its coordinates, and average them out using M = mean(A) - the problem I have is with accessing the neighbouring elements!
Any help would be great!
0 Kommentare
Akzeptierte Antwort
Sean de Wolski
am 17 Mai 2011
%Boundaries included
A2 = conv2(double(A),ones(3),'same')/9;
idx = A > 200; %simulating you're threshold
A(idx) = A2(idx);
This will yield a matrix with a windowing averaged matrix (A2) and select points in A that don't meet a criteria and replace them.
%Boundaries kept
A2 = conv2(double(A),ones(3),'valid')/9;
Apart = A(2:end-1,2:end-1);
idx = Atemp > 200; %simulating you're threshold
Atemp(idx) = A2(idx);
A(2:end-1,2:end-1) = Atemp;
3 Kommentare
Sean de Wolski
am 17 Mai 2011
Yes, you need to convert A to double first. See the first line of my answer.
Sean de Wolski
am 17 Mai 2011
Also, note: this answer is replacing border elements. It would be straightforward to change it.
Weitere Antworten (1)
Andrei Bobrov
am 17 Mai 2011
variant
Aout = A;
Aout(2:end-1,2:end-1) = conv2(A,ones(3),'valid')/9;
% or "8" and [1 1 1;1 0 1;1 1 1]?
MORE EDIT
2 variants
1.
Aout(2:end-1,2:end-1) = conv2(A,ones(3),'valid')/9;
2.
Aout(2:end-1,2:end-1) = conv2(A,[1 1 1;1 0 1;1 1 1],'valid')/8;
4 Kommentare
Sean de Wolski
am 17 Mai 2011
Why don't you just run your for loop from 1:9?
for ii = 1:9
A = imread(...)
A2 = conv2(A,ones(3),'same')/9;
idx = A > 200; %simulating you're threshold
A(idx) = A2(idx);
%Do something with A now that it's smoothed
end
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!