How to form a matrix from a coding of a graph?
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I have coding of a graph (vertices and edges) to find characteristic polynomial and eigen values. I need to view them in matrix form. Do we have coding to form a matrix?
clc;
clear all;
n = input('Enter the order of the inner path n = ');
m = 2*n+2
% undirected tree
T_1 = zeros(m);
T_1(1,2) = 1;
for i = 2 : n-1
T_1(i,i+1) = 1;
T_1(i,n+i-1) = 1;
T_1(i,(2*n)+i-3) = 1;
end
for i = 1 : m-1
for j = i+1 : m
T_1(j,i) = T_1(i,j);
end
end
% disp(T_1);
% characteristic polynomials
C_1 = charpoly(T_1);
disp(C_1)
% Eigenvalues of all
disp(eig(T_1))
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Antworten (2)
Avinash
am 14 Okt. 2022
Hi Andrew,
As like you have filled the values into the input matrix, you can also fill the values of output into a matrix. You can go through the following link of one such example:
Regards
Avinash
0 Kommentare
Dongyue
am 17 Nov. 2022
Hi Andrew,
If you want to reshape the vector into matrix, you can use function reshape(), you can go through the documentation of reshape function with the following link:
if you already know the dimensions of the expected results, you can pre-allocate a empty matrix using functions zeros() or ones(), and then fill values into the matrix. You can go through the documentation of zeros/ones function with the following link:
if you want to combine your results into one matrix in stack, you can also use cat() function, but you need to make sure the dimension of your results are consistent. For more information of cat function, please go through the link below:
Best,
Dongyue
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