MATLAB Answers

How to smooth plot without affecting the data. While I used smooth in plots, the data was reduced at some points.

17 views (last 30 days)
For example P = [0.8449;1.9194;3.6072;4.8034;6.1154;6.8659;7.2927;6.8533;4.8565;2.9631;1.2971]
Now when I use smooth
Ps = smooth(P)
the resulting figure is
in the P there is value above 7, but in plot the curve is not even touching 7.
Kindly anyone help.
Thanks and regards

Accepted Answer

Mathieu NOE
Mathieu NOE on 25 Feb 2021
to have a smoothed curved that goes closer to your input points, you have to interpolate first to have more data points, then smooth
I prefered my own version of data smoothing vs the movmean function (better handling of start / end points)
here is my result : yellow is the improved smoothing after interpolation, orange is without interpolation
P = [0.8449;1.9194;3.6072;4.8034;6.1154;6.8659;7.2927;6.8533;4.8565;2.9631;1.2971]
x = 1:length(P);
% Ps = movmean(P,5)
Ps = myslidingavg(P,5);
% increase points density and smoothing with myslidingavg
xx = linspace(1,length(P),200);
yy = interp1(x,P,xx,'pchip');
% yys = movmean(yy,25);
yys = myslidingavg(yy,25);
function out = myslidingavg(in, N)
% The function 'slidingavg' implements a one-dimensional filtering, applying a sliding window to a sequence. Such filtering replaces the center value in
% the window with the average value of all the points within the window. When the sliding window is exceeding the lower or upper boundaries of the input
% vector INPUT_ARRAY, the average is computed among the available points. Indicating with nx the length of the the input sequence, we note that for values
% of N larger or equal to 2*(nx - 1), each value of the output data array are identical and equal to mean(in).
% * The input argument INPUT_ARRAY is the numerical data array to be processed.
% * The input argument N is the number of neighboring data points to average over for each point of IN.
% * The output argument OUTPUT_ARRAY is the output data array.
if (isempty(in)) | (N<=0) % If the input array is empty or N is non-positive,
disp(sprintf('SlidingAvg: (Error) empty input data or N null.')); % an error is reported to the standard output and the
return; % execution of the routine is stopped.
end % if
if (N==1) % If the number of neighbouring points over which the sliding
out = in; % average will be performed is '1', then no average actually occur and
return; % OUTPUT_ARRAY will be the copy of INPUT_ARRAY and the execution of the routine
end % if % is stopped.
nx = length(in); % The length of the input data structure is acquired to later evaluate the 'mean' over the appropriate boundaries.
if (N>=(2*(nx-1))) % If the number of neighbouring points over which the sliding
out = mean(in)*ones(size(in)); % average will be performed is large enough, then the average actually covers all the points
return; % of INPUT_ARRAY, for each index of OUTPUT_ARRAY and some CPU time can be gained by such an approach.
end % if % The execution of the routine is stopped.
out = zeros(size(in)); % In all the other situations, the initialization of the output data structure is performed.
if rem(N,2)~=1 % When N is even, then we proceed in taking the half of it:
m = N/2; % m = N / 2.
else % Otherwise (N >= 3, N odd), N-1 is even ( N-1 >= 2) and we proceed taking the half of it:
m = (N-1)/2; % m = (N-1) / 2.
end % if
for i=1:nx, % For each element (i-th) contained in the input numerical array, a check must be performed:
dist2start = i-1; % index distance from current index to start index (1)
dist2end = nx-i; % index distance from current index to end index (nx)
if dist2start<m || dist2end<m % if we are close to start / end of data, reduce the mean calculation on centered data vector reduced to available samples
dd = min(dist2start,dist2end); % min of the two distance (start or end)
dd = m;
end % if
out(i) = mean(in(i-dd:i+dd)); % mean of centered data , reduced to available samples at both ends of the data vector
end % for i

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by