struggling with shifting an image using non-integer offset

1 Ansicht (letzte 30 Tage)
Alex
Alex am 12 Mai 2013
Kommentiert: Gustav Shen am 15 Mai 2017
I am not sure I understand the fact that the image's resolution 1500x2000 (integer values) pixels and offset_X = -3.0314 and offset_Y = 1.2432.
How to go about shifting the image taking into account the offset?

Akzeptierte Antwort

Matt J
Matt J am 12 Mai 2013
Use IMTRANSFORM, griddedInterpolant(), or INTERP2.
  2 Kommentare
Alex
Alex am 12 Mai 2013
Thank you for the advice. Could you please, correct the code below based on interp2. Let's say I have an image (size 971x1471) assigned to variable Im. Offset for this image is offset_X = -3.0314 and offset_Y = 1.2432. I need to get the image ImC (corrected image shifted using the offset above). After reading about interp2 I came up with the next code with MATLAB error message leaping at me. Please, guide me here.
[xx,yy] = ndgrid(1:971,1:1471);
xx = xx(:);
yy = yy(:);
xxShifted = xx + offset_X;
yyShifted = yy + offset_Y;
ImC=Im;
ImC(:) = interp2(xx,yy,Im(:),xxShifted,yyShifted);
Error using griddedInterpolant The grid vectors are not strictly monotonic increasing.
Error in interp2/makegriddedinterp (line 220) F = griddedInterpolant(varargin{:});
Error in interp2 (line 125) F = makegriddedinterp({X, Y}, V, method);
Bjorn Gustavsson
Bjorn Gustavsson am 13 Mai 2013
You dont need to (:) xx, yy and Im just send them into interp2 as they are.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Geometric Transformation and Image Registration finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by