where my code is wrong
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hello professionals can you plz help me in this code i want to display a at decrypted part but there is no value .plz help in code where i am wrong ...mostly the value of c3 come in form of 4.1038e+216...according to me if c(3) be made interger then code will be ok...but how it can be....as my code is
|matlab code for cryptography:|
% % %Encryption
for j=1:x
c1(j)=l_mod(c(j),e,n);
c3=g.^c1(j);
t=m*m;
c2=l_mod(r,m,t);
cipher(j)=c3*c2;
end
disp('Cipher Text of the entered Message:');
disp(cipher);
% % %Decryption
for j=1:x
m1(j)=l_mod(cipher(j),lamda,t);
m2(j)=m1(j)-1;
m3(j)=m2(j)/m;
m4=l_mod(mew,1,m);
m5=m3(j )*m4;
msg(j)=l_mod(m5,d,n)
end
disp('Decrypted Message is')
dec=char(msg)
|answer coming after running code:|
The value of (n) is: 391
The public key (e) is: 3
The value of (g) is: 552
The private key (m)is: 551
Enter the message: a
ASCII Code of the entered Message:
97
c1 =
79
c3 =
4.1038e+216
t =
303601
c2 =
141151
cipher =
5.7926e+221
Cipher Text of the entered Message:
5.7926e+221
msg =
15.9049
Decrypted Message is
dec =
Antworten (4)
It appears to be l_mod's fault. Where does l_mod come from? What does it do, and what makes you sure that it is working?
rjnt Kaur
am 12 Mai 2013
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3 Kommentare
Matt J
am 12 Mai 2013
You missed my point. l_mod is not working correctly. Therefore you must debug it. We cannot help you debug it because we cannot see it.
rjnt Kaur
am 13 Mai 2013
Bjorn Gustavsson
am 13 Mai 2013
c.^mod(e,n)
rjnt Kaur
am 12 Mai 2013
0 Stimmen
rjnt Kaur
am 12 Mai 2013
0 Stimmen
1 Kommentar
Image Analyst
am 12 Mai 2013
Please add comments to someone's answer, and edit them if you want to add stuff, rather than adding additional, new "Answers", which actually aren't answers at all.
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