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Error using movmax index

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david crowley
david crowley am 21 Feb. 2021
Kommentiert: Walter Roberson am 10 Jun. 2021
I need to find the number of periods since a stock price recorded an 14-day high. My proposed method was to use the following andpossibly subtract the index from the current row:
n = 14
[M,I] = movmax(high,[n-1 0],'omitnan');
However, I return - "error using movmax. Too many output arguments."
Can someone please assist in my methodology.

Antworten (1)

Walter Roberson
Walter Roberson am 21 Feb. 2021
There is no syntax for movmax() in which it returns a second output. It does not return the indices of the local maxima.
  4 Kommentare
Raphael Willi
Raphael Willi am 10 Jun. 2021
Loop how?
Walter Roberson
Walter Roberson am 10 Jun. 2021
wid = 5;
N = 50;
signal = randi([-9, 9], 1, N)
signal = 1×50
-4 -9 -5 8 -6 -2 7 -3 6 -1 5 6 3 -5 -3 -3 -8 0 -8 7 -9 -3 6 0 4 2 -8 -9 3 -3
for K = 1 : N - wid + 1
[M(K), relI] = max(signal(K:K+wid-1));
I(K) = K + relI - 1;
end
M
M = 1×46
8 8 8 8 7 7 7 6 6 6 6 6 3 0 0 7 7 7 7 7 6 6 6 4 4 3 3 3 3 1
I
I = 1×46
4 4 4 4 7 7 7 9 9 12 12 12 13 18 18 20 20 20 20 20 23 23 23 25 25 29 29 29 29 34

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