Dear members
I have matrix with size M*N and vector with size 1*K
I want to create a null vector with length of N - length of K
I tried this :
V=zeros(1,length(N)-length(K));
but it doesn't work. Any solution please ?
Thank you.

3 Kommentare

Just Manuel
Just Manuel am 18 Feb. 2021
this would be easier if you told us what is not working. Do you get an error message? Or just an unexpected result?
As it stands, your code is valid.
Afluo Raoual
Afluo Raoual am 18 Feb. 2021
I get an unexpected result which is:
1*0 empty double row vector
Just Manuel
Just Manuel am 18 Feb. 2021
Yep, then go with Bjorn Gustavsson's answer.
Cheers
Manuel

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Bjorn Gustavsson
Bjorn Gustavsson am 18 Feb. 2021

0 Stimmen

First off if you've done something like:
N = 12;
M = 14;
K = 7;
Mtr = randn(M,N);
V = rand(1,K);
V=zeros(1,length(N)-length(K));
Then you only check the length of the 1-by-1 arrays N and K - and the difference of that is zero. If your N and K are your arrays you might have run into a situation where N < K, because this also happens when N < K. Perhaps you've mixed up the dimensions of your matrix and you meant to make something like this:
V=zeros(1,M - K);
HTH

4 Kommentare

Afluo Raoual
Afluo Raoual am 18 Feb. 2021
No, in my case N > K
I have N=7774 and K=5832
When I put zeros(1,7774-5832) it works, but with zeros(1, length(N)-length(K)) it doesn't work
Yes, then omit the length call. Just do
zeros(1, N-K);
Cheers
Manuel
Afluo Raoual
Afluo Raoual am 18 Feb. 2021
It's done. Thank you :)
Just Manuel
Just Manuel am 18 Feb. 2021
You're welcome.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu MATLAB finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by