How to obtain the filtered Index of Cell Array

3 Ansichten (letzte 30 Tage)
Kushan
Kushan am 6 Mai 2013
% This is the code
AllNames= {'A.1';'A.1';'A.10';'A.10';'A.10';'A.10';'A.15';'A.15';'A.16' ;'A.17';'A.17';'A.17';'A.17';'A.17';'A.20A';'A.20A';'A.20A';'A.20A'};
B=[2;6;3;4;5;1;8;6;4;3;2;8;6;1;6;8;9;2];
ide_names=unique(AllNames(1:end,1)) ;
for i= 1:length(ide_names)
index=find(AllNames(:,1)==ide_names(i,1));
data.Name(1,i)=ide_names(i,1);
data.Value=B(index,1);
end
% I want to create a new data struct(data) using the filtered Index from Cell Array A with values contain in B column vector. However, Once I ran the code below error is poping up.
_Undefined function 'eq' for input arguments of type 'cell'.
Error in a (line 6) index=find(AllNames(:,1)==ide_names(i,1));_
% could someone help me out, please
  1 Kommentar
Jan
Jan am 6 Mai 2013
I have formatted your code. It is easy: mark it with the mouse, hit the "{} Code" button, care for a blank line before and after the code.

Melden Sie sich an, um zu kommentieren.

Antworten (3)

Andrei Bobrov
Andrei Bobrov am 6 Mai 2013
Bearbeitet: Andrei Bobrov am 6 Mai 2013
AllNames= {'A.1';'A.1';'A.10';'A.10';'A.10';'A.10';'A.15';'A.15';'A.16' ;'A.17';'A.17';'A.17';'A.17';'A.17';'A.20A' ;'A.20A';'A.20A';'A.20A'};
B=[2;6;3;4;5;1;8;6;4;3;2;8;6;1;6;8;9;2];
[a,c,c] = unique(AllNames); %[EDIT}
bb = accumarray(c,B,[],@(x){x});
data = struct('Name',a,'Value',bb);

Kushan
Kushan am 6 Mai 2013
Thanks a lot for your quick response. But below line is not working
[a,~,c] = unique(AllNames,'stable');
The below error massage is popping up
[a,~,c] = unique(AllNames,'stable');
Error using cell/unique (line 28)
Unrecognized option.
Please help me out

Jan
Jan am 6 Mai 2013
You can change the line:
index=find(AllNames(:,1)==ide_names(i,1)); % ERROR
to
index = strcmp(AllNames(:,1), ide_names{i,1});
But using the outputs of unique is faster.

Kategorien

Mehr zu Startup and Shutdown finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by