Nested for loop portfolio optimization

1 Ansicht (letzte 30 Tage)
Kevin van Berkel
Kevin van Berkel am 2 Mai 2013
Hi guys,
I am probably doing something utterly silly which holds me back from retrieving the desired results.
I have two matrices: Matrix(A), which is a vector containing returns from three risky assets, and Matrix C, which consists of optimally genereated weights of those risky assets. To obtain the return, I wrote the following loop:
for i = 1:155
for j = 1:155
returns = A(i,:)*C(j,:)'
end
end
This code yields a 1x155 matrix, exactly as I asked for, But, the answers are not correct.
Does anyone have a clue what I do wrong here?
Thanks for the effort!
Cheers,
Kevin
  2 Kommentare
Matt J
Matt J am 2 Mai 2013
The code you've shown returns a scalar, not a 1x155 vector. You should show us the code you're actually using.
Kevin van Berkel
Kevin van Berkel am 3 Mai 2013
Hi Matt, thanks for your response.
s = size(A);
C = zeros(s);
for j1 = 1:s(1)
C(j1,:) = A(j1,:)*B((j1-1)*s(2)+1:j1*s(2),:);
end
and this yields me the the weight's vector 'C'. 'A' is also a 155x3 vector. So I only need to multiply every row with the transpose of the other vector. E.G. A(row 1,col 1-3)*C'(row 1, col 1-3)
Hope this clarifies my question. Thanks!

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Kevin van Berkel
Kevin van Berkel am 3 Mai 2013
Hi Matt, thanks for your response.
s = size(A);
C = zeros(s);
for j1 = 1:s(1)
C(j1,:) = A(j1,:)*B((j1-1)*s(2)+1:j1*s(2),:);
end
and this yields me the the weight's vector 'C'. 'A' is also a 155x3 vector. So I only need to multiply every row with the transpose of the other vector. E.G. A(row 1,col 1-3)*C'(row 1, col 1-3)
Hope this clarifies my question. Thanks!

Kategorien

Mehr zu Quadratic Programming and Cone Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by