How can get roots of polynomial having variables in denominator.?
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Vinothkumar Sethurasu
am 12 Feb. 2021
Kommentiert: Vinothkumar Sethurasu
am 12 Feb. 2021
Let
F(x)= (x^2+1)/(x+1)+(2*x^2+3)/(x+2)=0,
With syms x,
How can we find the roots of F(x).?
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KSSV
am 12 Feb. 2021
Read about vpasolve.
syms x
F = (x^2+1)/(x+1)+(2*x^2+3)/(x+2)==0 ;
r = vpasolve(F)
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