Using the answer of inputdlg into a Matlab Expression

1 Ansicht (letzte 30 Tage)
Alessandro
Alessandro am 30 Apr. 2013
Bearbeitet: MoeIsKing am 14 Nov. 2018
Hello everybody,
I am trying to write some piece of code which asks for the name of a previously defined variable and uses the answer in some calculations. Everything works fine when I use 'input' to ask for that name. But I want to use the 'inputdlg' command. The problem is that 'inputdlg' returns user input in a cell array. I tried converting the cell with 'str2double' but that only works for numbers (won't work when trying to convert the name of the variable!). This is the piece of code:
Source = inputdlg('Name given to the vector containing the sample: ');
Fs = inputdlg('Sampling Frequency: '); % Sampling frequency
Fs = str2double(Fs);
Source = str2double(Source(1,1));
T = 1/Fs; % Sample time
L = length(Source); % Length of signal
t = (0:L-1)*T; % Time vector
NFFT = 2^nextpow2(L); % Next power of 2 from length of y
Y=fft(Source,NFFT)/L;
  2 Kommentare
Azzi Abdelmalek
Azzi Abdelmalek am 30 Apr. 2013
What is the error message?
Alessandro
Alessandro am 30 Apr. 2013
Bearbeitet: Alessandro am 30 Apr. 2013
For example, if the vector I want to select is 'A', 'Source' vector will be composed of a single entry 'A' instead of being equal to the original vector. Note this does not happen when using 'input' command instead of 'inputdlg'.

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Antworten (2)

Azzi Abdelmalek
Azzi Abdelmalek am 30 Apr. 2013
Use
Source = char(Source)
  2 Kommentare
Alessandro
Alessandro am 30 Apr. 2013
That doesn't work as well, because the so-created Source is a char-type array containing 1 entry instead of being set equal to the vector specified in the inputdlg box.
Alessandro
Alessandro am 30 Apr. 2013
This helped anyways. By using
Source = eval(char(Source(1,1)))
i got it to work. Not very elegant, but it's still something. Thanks!

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MoeIsKing
MoeIsKing am 14 Nov. 2018
Bearbeitet: MoeIsKing am 14 Nov. 2018
Source = eval(char(inputdlg())) helps
THANKS

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