how to plot linear regression ?

4 Ansichten (letzte 30 Tage)
Rand Ardat
Rand Ardat am 8 Feb. 2021
Kommentiert: Star Strider am 8 Feb. 2021
i want to do linear regression for : log(vp)=A-B/(T+273.15) !!
vp = [ 1 5 10 20 40 60 100 200 400 760]
T = [-36.7 -19.6 -11.5 -2.6 7.6 15.4 26.1 42.2 60.6 80.1]
y = log10(vp);
x = 1./(T+273.15);
% fit the polynomial
p = polyfit(x,y,1)
% p = -2035.33 8.75201
y=polyval(p,x)
plot(T,y,'or',T,vp,'b')
xlabel('T (C)')
ylabel('vp (mm Hg)')

Akzeptierte Antwort

Star Strider
Star Strider am 8 Feb. 2021
Try this:
figure
plot(T,vp,'or',T,10.^y,'b')
xlabel('T (C)')
ylabel('vp (mm Hg)')
The rest of the code is unchanged.
  2 Kommentare
Rand Ardat
Rand Ardat am 8 Feb. 2021
thank you!
Star Strider
Star Strider am 8 Feb. 2021
As always, my pleasure!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

the cyclist
the cyclist am 8 Feb. 2021
Bearbeitet: the cyclist am 8 Feb. 2021
You should plot
plot(T,10.^y,'or',T,vp,'b')
because you did the regression on log10(y), not y itself.
vp = [ 1 5 10 20 40 60 100 200 400 760]
T = [-36.7 -19.6 -11.5 -2.6 7.6 15.4 26.1 42.2 60.6 80.1]
y = log10(vp);
x = 1./(T+273.15);
% fit the polynomial
p = polyfit(x,y,1)
% p = -2035.33 8.75201
y=polyval(p,x)
plot(T,10.^y,'or',T,vp,'b')
xlabel('T (C)')
ylabel('vp (mm Hg)')
Also, it looks like you plotted the data as a line, and the fit as individual circles. I expect you want the opposite, which is more conventional.

Kategorien

Mehr zu Linear and Nonlinear Regression finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by