Passing information between arrays

name3d = [1x31 char]    [1x31 char]    [1x31 char]
ct = 1
              for i = 1:length(name3d)
                  tableName{ct} = name3d(i)       
                  ct = ct + 1;
              end

This code results in:

tableName = {1x1 cell}    {1x1 cell}    {1x1 cell}

What I want is:

tableName = [1x31 char]    [1x31 char]    [1x31 char]

The intent here is to take an array of strings and append them onto an existing array without nesting. The nesting is making it impossible for me to export . . .

[James Tursa]

Typo in your posted code? The first iteration has ct = 0, which would result in tableName{0} = etc, which should have resulted in an error.

[Steve]

Fixed the typo. It was actually increased earlier on in the code. I just wanted to show it was defined and not complicate the whole thing with 30 lines of code . . .

Answer 1

[Steve]

tableName (ct) = name3d(i)

Use () instead of {}. This adds each instance on one at a time rather than as one array nested inside the other.

Solved.

Answer 2

[Sean de Wolski]

What's wrong with:

tableName = name3d

? It looks like it's already the desired result.

Answer 3

[Steve]

I can't do that because name3d is being appended onto tableName and there may be instances where there is data already stored in the array that I don't want to lose.