I have a question regarding matrix multiplication using for loop for a general matrix
n1=1; n2=4; n3=4; n4=2;
Ai is the general matrix from this to find the value of A1 ,A2 ,A3 and A4
Ai= [ni ni^2; cos(ni) sin(ni)]
Display of matrix A1,A2,A3 and A4
Display of A1*A2*A3*A4.

10 Kommentare

KSSV
KSSV am 29 Jan. 2021
What have you attempted?
shiv gaur
shiv gaur am 29 Jan. 2021
pl write the code
shiv gaur
shiv gaur am 29 Jan. 2021
for i=1:4
n1=1; n2=4; n3=4; n4=2;
%Ai is the general matrix from this to find the value of A1 ,A2 ,A3 and A4
Ai= [ni ni^2; cos(ni) sin(ni)]
display([A1 A2 A3 A4])
end
Walter Roberson
Walter Roberson am 29 Jan. 2021
n1=1; n2=4; n3=4; n4=2;
Ai= [ni ni^2; cos(ni) sin(ni)]
What that is supposed to tell you is that the matrices are
A1 = [n1, n1^2; cos(n1), sin(n1)]
A2 = [n2, n2^2; cos(n2), sin(n2)]
A3 = [n3, n3^2; cos(n3), sin(n3)]
A4 = [n4, n4^2; cos(n4), sin(n4)]
shiv gaur
shiv gaur am 29 Jan. 2021
yes
shiv gaur
shiv gaur am 29 Jan. 2021
pl any one write the code of multiplication of this
Walter Roberson
Walter Roberson am 29 Jan. 2021
expression_that_pulls_out_A1 * expression_that_pulls_out_A2 * expression_that_pulls_out_A3 * expression_that_pulls_out_A4
For expression_that_pulls_out_An substitute appropriate code according to how you choose to implement creating variables in a loop. For example if you put them as rows in a table object, MYTABLE then
MYTABLE{1,1} * MYTABLE{2,1} * MYTABLE{3,1} * MYTABLE{4,1}
shiv gaur
shiv gaur am 29 Jan. 2021
write code
I just did.
%{
MYTABLE{1,1} * MYTABLE{2,1} * MYTABLE{3,1} * MYTABLE{4,1}
%}
That is code.
I will give you a further hint:
P = cell(10,1);
for K = 1 : 10
P{K} = randi(10,1,50);
end
Total = 0;
for K = 1 : 10
Total = Total + P{K};
end
plot(Total)

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