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Selection of row from a matrix

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raj singh
raj singh am 20 Apr. 2013
i have a matrix,and i want remove that row in which numbers repeated
A= [3 5 5
6 9 1
7 5 7
2 4 6];
Ans: A=[6 9 1;2 4 6]
i used "for loop" for this problem, i want to ask there is any direct command to find the Ans. pls give me the suggestion.....

Akzeptierte Antwort

per isakson
per isakson am 20 Apr. 2013
Post the question at Cody:). It's a little exercise with logicl indexing.
>> A( any( diff( sort( A, 2 ), 1, 2 ) == 0, 2 ), : ) = []
A =
6 9 1
2 4 6
>>
  4 Kommentare
per isakson
per isakson am 20 Apr. 2013
Works here
A= [1 1 1 2
1 2 3 4
1 2 4 5
3 4 3 3];
A( any( diff( sort( A, 2 ), 1, 2 ) == 0, 2 ), : ) = []
A =
1 2 3 4
1 2 4 5
>>
raj singh
raj singh am 20 Apr. 2013
:) yaa, its working, it was my fault. thanks

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