Filter löschen
Filter löschen

How do I take the derivative of my plot?

260 Ansichten (letzte 30 Tage)
Alejandro
Alejandro am 19 Apr. 2013
Bearbeitet: Torsten am 23 Jan. 2023
I have my temperature in the y axis, and my distance in the x. I have them all plotted out and I have the data too, how can I take the derivative of the plot?

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 19 Apr. 2013
dy=diff(y)./diff(x)
plot(x(2:end),dy)
  8 Kommentare
Ali
Ali am 23 Jan. 2023
does that work when the derivative at some data points has 2 values (before and after the data point)?
I mean the derivative of the plot is not continuous in all points.
Torsten
Torsten am 23 Jan. 2023
Bearbeitet: Torsten am 23 Jan. 2023
If you only have discrete values for x and y, there is no method to tell you whether there is a discontinuity in the derivative of y in a point x_i.
You can compare (y(i+1)-y(i))/(x(i+1)-x(i)) with (y(i)-y(i-1))/(x(i)-x(i-1)), but even if both differ significantly, it's not possible to decide whether there is a discontinuity in the derivative at x=x(i).

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Shaun VanWeelden
Shaun VanWeelden am 19 Apr. 2013
Call polyfit to generate your polynomial (if you don't already have a polynomial)
Call polyder to get derivative of your fitted line
Call polyval with your original X values to get the Y values of your derivative and plot that with hold on so it doesn't erase your original plot
  1 Kommentar
John D'Errico
John D'Errico am 31 Jul. 2016
Note that polyfit (any polynomial fit) will often be a terribly poor choice here, since many curves are not well fit by a polynomial model. For example, consider points that lie on the perimeter of a circle, or the function sqrt(x), near x==0. Or the function sin(x), over multiple periods. Or a classic problem function for polynomial fits, 1/(1+x^2).

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Polynomials finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by