Filter löschen
Filter löschen

Why is Matlab not abled to run this as a parfor loop?

1 Ansicht (letzte 30 Tage)
Matthias
Matthias am 19 Apr. 2013
I want to run a loop like this as a parfor loop. In my eyes it shouldn't matter in which order the different iterations are called. 'a' is only used as reduction variable.
a = zeros(1,5);
parfor i= 1:1000
dts = randi(10)-1;
if dts == 0
a(1) = a(1) + 2;
elseif dts <= 5
a(dts) = a(dts) +1;
end
end
This is the error, which i get:
Error using Test (line 2) Error: The variable a in a parfor cannot be classified.
See Parallel for Loops in MATLAB, "Overview". Why wouldn't Matlab allow this program? How do i fix it?
Edit: Since the Codeblock-function doesn't seem to work: http://pastebin.com/FUHFe61T
  2 Kommentare
Sean de Wolski
Sean de Wolski am 19 Apr. 2013
That doesn't even work with a regular for-loop. That should always be the first step: making sure it works with a regular loop.
Matthias
Matthias am 19 Apr. 2013
I had a little typo. It is supposed to be randi(10) not rand(10).

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Friedrich
Friedrich am 19 Apr. 2013
Bearbeitet: Friedrich am 19 Apr. 2013
Hi,
MATLAB thinks a is a sliced variable and you get troubles with the indices here. I think in such a case its better to use a Reduction Variable like this:
X = zeros(1,5);
parfor i= 1:1000
a = zeros(1,5);
dts = randi(10)-1;
if dts == 0
a(1) = (a(1) + 2);
elseif dts <= 5
a(dts) = a(dts) +1;
end
X = X + a;
end
For more information about variable types see here:

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by