Can't use laplace transformed expression with transfer function.

When i laplace transform my expression ('r2') it becomes "sym" and i cant use it with any system or transfer function in the 's'-domain.
('r1') is numerically equivalent, but declared manually. it works fine.
Is there a way to make Laplace transforms become "tf"?

 Akzeptierte Antwort

Rohit Pappu
Rohit Pappu am 29 Jan. 2021
A plausible solution is as follows
% Collect the coefficients of r2
h = collect(r2);
% Split the coefficients into numerator and denominator
[ii,jj] = numden(h);
% Convert the coefficients into numerical values
num = sym2poly(ii);
den = sym2poly(jj);
% Generate Transfer function from the above coefficients
model= tf(num,den);

2 Kommentare

There can be additional work needed if there is a delay on the system. That shows up as an exp() term symbolically.
Not simple, but it did work! thanks guys!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu MATLAB finden Sie in Hilfe-Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by