pid for dynamic malaria

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af af
af af am 21 Jan. 2021
Beantwortet: Sam Chak am 20 Aug. 2022
Can the pid controller be set to malaria dynamics?
  7 Kommentare
af af
af af am 24 Jan. 2021
i put [T,Y]=ode45(@malariaSEIRS,tspan,y0);
but it still gives an error
Walter Roberson
Walter Roberson am 24 Jan. 2021
You appear to have functions named u1 and u2 and u3 that each take t as a parameter, but you have not posted the code for those functions.

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Antworten (1)

Sam Chak
Sam Chak am 20 Aug. 2022
Not sure what are PID controllers for the Malaria dynamics. However, by the mathematical manipulation, you can probably propose as shown below to keep the disease spread under control.
tspan = [0 10];
y0 = zeros(1, 7);
[T, Y] = ode45(@malariaSEIRS, tspan, y0);
plot(T, Y), grid, xlabel('Days')
legend('S_h', 'E_h', 'I_h', 'R_h', 'S_v', 'E_v', 'I_v', 'location', 'East')
Y(end, :)
ans = 1×7
0.0001 1.5163 0.4067 0.0021 0.9990 125.2982 0.8853
function dydt = malariaSEIRS(t, y)
dydt = zeros(7, 1);
% parameters
phi = 0.502;
epsilon = 0.2;
beta = 0.8333;
landa = 0.09;
muh = 0.00004;
muv = 0.1429;
k = 0.7902;
a1 = 1/17;
a2 = 1/18;
lambdah = 0.2;
lambdav = 1000;
tau = 0.01 - 0.7;
psi = 0.05;
b = 0.005;
p = 0.25;
Sh = 1100;
Eh = 200;
Ih = 400;
Rh = 0;
Sv = 800;
Ev = 250;
Iv = 80;
Nh = Sh + Eh + Ih + Rh;
% Nv = Sv + Ev + Iv;
betam = beta*epsilon*phi*Iv/Nh;
landav = landa*epsilon*phi*Ih/Nh;
% states
Sh = y(1);
Eh = y(2);
Ih = y(3);
Rh = y(4);
Sv = y(5);
Ev = y(6);
Iv = y(7);
% u1, u2, u3
k3 = 1; % adjust this parameter
u3 = ((k3 - muv)*Iv + a2*Ev)/p;
u2 = 0;
k1 = 1; % adjust this parameter
u1 = (- (k1 - p*u3 - muv - 1*landav)*Sv - lambdav)/landav;
% Malaria dynamics
dydt(1) = lambdah + (k*Rh) - (1 - u1)*betam*Sh - muh*Sh;
dydt(2) = (1 - u1)*betam*Sh - (a1 + muh)*Eh;
dydt(3) = a1*Eh - (b + tau*u2)*Ih - (psi + muh)*Ih;
dydt(4) = (b + tau*u2)*Ih - (k + muh)*Rh;
dydt(5) = lambdav - (1 - u1)*landav*Sv - p*u3*Sv - muv*Sv;
dydt(6) = (1 - u1)*landav*Sv - p*u3*Ev - (a2 + muv)*Ev;
dydt(7) = a2*Ev - p*u3*Iv - muv*Iv;
end

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