Filter löschen
Filter löschen

How can I plot multiple 2d plots with a z value that changes the value of each line?

4 Ansichten (letzte 30 Tage)
Hello,
I have x, y and z data. I would like to plot x and y data for all different z values using plot, and vary each line color based on the corresponding z value. I want to specfically use plot so that I may use straight lines, and so I am not interested in using scatter, nor contour.
For example...
colormap(jet(3))
hold on
plot(linspace(0,10),linspace(0,10)+1)
plot(linspace(0,10),2.*linspace(0,10)+1)
plot(linspace(0,10),.25.*linspace(0,10))
hold off
hc=colorbar;
cb=1:5:10;
set(hc,'YTick',cb, 'YTickLabel', {'1','5','10'})
This will return...
which is not what I want for multiple reasons. First, the lines do not match the jet colormap settings I have inputted. Second, the colorbar does not have all the tick labels. How can I fix this so that the color of the plot lines matches the colorbar and the ytick labels are shown correctly?

Akzeptierte Antwort

Mathieu NOE
Mathieu NOE am 15 Jan. 2021
hello Alessandro
check this please
n = 3;
z = [1 2 0.25]';
z = sort(z,'ascend');
x = linspace(0,10);
y = z*x;
data_min = min(y,[],'all');
data_max = max(y,[],'all');
map = colormap(jet(n));
[mmap,nmap] = size(map);
hold on
for ci = 1:n
h = plot(x,y(ci,:));
set(h, 'Color', map(ci,:)) ;
end
hold off
hc=colorbar;
cb=(1/(2*n):1/n:1);
set(hc,'YTick',cb, 'YTickLabel', num2str(z))
hc.Title.String = "Z range";
  2 Kommentare
Alessandro Maria Laspina
Alessandro Maria Laspina am 16 Jan. 2021
Bearbeitet: Alessandro Maria Laspina am 16 Jan. 2021
How can I make this work for tiledlayout? If I use a tilelayout structure, what will end up happening is that the colorbar will go from a discrete color representation to a gradient where it gradually changes from one color to another, and it makes it harder to distinguish.
EDIT: nevermind it also works with tiledlayout.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Colormaps finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by