Hello, don't know why the discrepancy.
function fcno
y0=linspace(0,2,20);
t0=linspace(0,3,100);
figure(1)
close(1)
figure(1)
options=odeset('RelTol',1e-5);
subplot(1,3,1)
hold on
for k=1:20
[t,y]=ode45(@fun,t0,y0(k),options);
plot(t,y,'b')
end
title('ode')
subplot(1,3,2)
hold on
t=t0;
for k=1:20
f2=y0(k)*exp(t)./(1+(exp(t)-1)*y0(k));
plot(t,f2,'r')
end
title('solution')
%%
lon=101;
t=linspace(0,3,lon);
h=3/(lon-1);
y0=linspace(0,2,20);
subplot(1,3,3)
hold on
for m=1:20
y=zeros(1,lon);
y(1)=y0(m);
for k=1:100
y(k+1)=y(k)+h*y(k)*(1-y(k));
end
plot(t,y,'g')
end
plot([0 3],[0 0],'m--','linewidth',3)
plot([0 3],[1 1],'m--','linewidth',3)
title('my ode')
%%
function [t,yp]=fun(t,y)
yp=y*(1-y);
end
end

2 Kommentare

Mischa Kim
Mischa Kim am 14 Jan. 2021
Hi Bobby, can you please provide more information of what you are trying to accomplish and the (unexpected) results you receive?
Bobby Fischer
Bobby Fischer am 14 Jan. 2021
Thanks Mischa. All clear.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

J. Alex Lee
J. Alex Lee am 14 Jan. 2021

0 Stimmen

You have a syntax error on what your odefun is returning. To fix:
function [yp]=fun(t,y)
yp=y*(1-y);
end

Weitere Antworten (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by