game of life help please

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androSLO
androSLO am 11 Apr. 2013
Beantwortet: arushi am 28 Aug. 2024
Hello,
I have to do for school a game named "game of life". I have a network in which are some cells alive( matric, where are live cells marked with 1 and other with 0). Rules of survival are simple:
a)if has live cell less than 2 neighbours dies of loneliness
b)if has live cell more than 3 neighbours dies from overpopulation
c)if has dead cell exactly 3 neighbours it became alive
i really don't know how to do this..:( sorry Please help me i would be very gratefull everybody.

Antworten (1)

arushi
arushi am 28 Aug. 2024
Hi Androslo,
Here is an example implementation for your reference -
function gameOfLife(initialState, numIterations)
% initialState: Matrix representing the initial state of the grid
% numIterations: Number of iterations to simulate
% Get the size of the grid
[rows, cols] = size(initialState);
% Initialize the current state
currentState = initialState;
% Define the possible neighbor positions (relative)
neighborDeltas = [-1, -1; -1, 0; -1, 1; 0, -1; 0, 1; 1, -1; 1, 0; 1, 1];
% Simulation loop
for iter = 1:numIterations
% Create a new state matrix
newState = zeros(rows, cols);
% Iterate over each cell in the grid
for r = 1:rows
for c = 1:cols
% Count the number of live neighbors
liveNeighbors = 0;
for i = 1:size(neighborDeltas, 1)
neighborRow = r + neighborDeltas(i, 1);
neighborCol = c + neighborDeltas(i, 2);
% Check if the neighbor is within bounds and alive
if neighborRow >= 1 && neighborRow <= rows && ...
neighborCol >= 1 && neighborCol <= cols && ...
currentState(neighborRow, neighborCol) == 1
liveNeighbors = liveNeighbors + 1;
end
end
% Apply the rules of the Game of Life
if currentState(r, c) == 1
% Rule a: Less than 2 neighbors
% Rule b: More than 3 neighbors
if liveNeighbors < 2 || liveNeighbors > 3
newState(r, c) = 0; % Cell dies
else
newState(r, c) = 1; % Cell survives
end
else
% Rule c: Exactly 3 neighbors
if liveNeighbors == 3
newState(r, c) = 1; % Cell becomes alive
end
end
end
end
% Update the current state
currentState = newState;
% Display the current state
disp(['Iteration: ', num2str(iter)]);
disp(currentState);
% Optional: Pause for a short time to visualize the evolution
pause(0.5);
end
end
Hope it helps.

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