Solving a matrix using MatLab?

I need help solving the following matrix
>> M = [1 0 2 1 18; 0 -3 -3 0 -8; -2 -3 0 0 -41; -1 0 -1 1 16]
I was able to get it to the following
>> M = [1 0 2 1 18; 0 1 1 0 2.6667; 0 2.3333 0 -.6667 5.2222; 0 0 1 2 34]
I'm stuck. Anybody willing to help me through this. Thanks in advance
It has to be reduced into RREF. What would my next step be?

Antworten (2)

Tobias
Tobias am 10 Apr. 2013

0 Stimmen

Do you have to do it manually? If you have MATLAB at your disposal, why not just use the rref-command?
rref(M)
^ That should fix your problem
Amed
Amed am 10 Apr. 2013

0 Stimmen

I have to do it manually and rref(M) at the end to show it's in RREF form

7 Kommentare

Tobias
Tobias am 10 Apr. 2013
Bearbeitet: Tobias am 10 Apr. 2013
Are you sure you have not made a mistake somewhere? I am not getting the same value as you have in your last step and going onwards from there, probably won't do you any good.
By the way: Use comment and not answer
Amed
Amed am 10 Apr. 2013
Error as in what? I'm solving using matlab so i'm not too sure where I went wrong.. I'll start from the beginning and step by step what I do
Amed
Amed am 10 Apr. 2013
Bearbeitet: Amed am 10 Apr. 2013
>> M = [1 0 2 1 18; 0 -3 -2 0 -8; -2 -3 0 0 -41; 1 0 -1 1 16];
>> M2=M;
>> M2(3,:) = M2(3,:)+(2*M2(1,:));
>> M2(4,:) = M2(4,:)-M2(1,:);
>> M3 = M2;
>> M3(3,:) = M3(3,:)+M3(2,:);
>> M3(3,:) = M3(3,:)-M3(2,:);
>> M3(3,:) = M3(3,:)-M3(2,:);
>> M3(2,:) = (-1/3)*M3(2,:)
end I end up with [1 0 2 1 18; 0 1 .6667 0 2.6667, 0 0 6 2 3, 0 0 -3 0 -2];
Amed
Amed am 10 Apr. 2013
I'm so lost...
Amed
Amed am 10 Apr. 2013
Anybody help, it's due like real soon. I'm stuck in the water on this one
Amed
Amed am 10 Apr. 2013
hello, anybody out there?
Amed
Amed am 10 Apr. 2013
yoyoyoyoyo

Diese Frage ist geschlossen.

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am 10 Apr. 2013

Geschlossen:

am 20 Aug. 2021

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