Not enough input arguments.

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Stefania Rauta
Stefania Rauta am 5 Jan. 2021
Kommentiert: the cyclist am 6 Jan. 2021
function P = Fillter(K)
dem=0;
%F=zeros(10001,2);
F(1,1)=K(1,1);
F(1,2)=K(1,2);
t=length(K(:,1));
for i=2:1:t
if (K(i,1)~=K(i-1,1))
F(i-dem,1)=K(i,1); F(i-dem,2)=K(i,2);
else
dem=dem+1;
end
end
P=F;
end
Line : F(1,1)=K(1,1); Not enough input arguments.
How to fix that?

Akzeptierte Antwort

the cyclist
the cyclist am 5 Jan. 2021
How are you calling the function? If you call it like this ...
Fillter()
then you will get that error because Fillter is expecting one input, and it is receiving zero inputs.
  2 Kommentare
Stefania Rauta
Stefania Rauta am 6 Jan. 2021
that's not the problem :(
the cyclist
the cyclist am 6 Jan. 2021
You didn't answer the question, though. How are you calling the function? Can you upload a complete set of code we can run, that gives the error? Because if I call it as follows
Fillter([1 2 3 4])
then the code runs to completion with no error.

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