Interpolating data from the graph
26 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
subbu
am 30 Dez. 2020
Kommentiert: subbu
am 31 Dez. 2020
The graph shown is plotted ductility Vs Time period of a system for four diifferent Ry . What i needed is to find the Ry s for particular ductility demand ( say 2) for the time period varying from 0 to 20 as shown in the graph. The Ry s need to find out using interpolation of the given graphs ( ie, in between the four Ry s given). can someone help with this problem??

2 Kommentare
Akzeptierte Antwort
Cris LaPierre
am 30 Dez. 2020
Ok, since you have all the data used to create the plot, you will just use the X and Y values as inputs to the interp1 function. For example, if I wanted to interpolate the values of each curve at T(s)=7, I would add the following to the bottom of your check.m script.
% interpolate at T(s) = 7
xq=7;
yq1 = interp1(Tn,meu1,xq);
yq2 = interp1(Tn,meu2,xq);
yq4 = interp1(Tn,meu4,xq);
yq8 = interp1(Tn,meu8,xq);
% visualize on the plot
plot(xq,yq1,'^')
plot(xq,yq2,'o')
plot(xq,yq4,'d')
plot(xq,yq8,'>')

7 Kommentare
Cris LaPierre
am 31 Dez. 2020
Bearbeitet: Cris LaPierre
am 31 Dez. 2020
In that case, you need to interpolate twice. First to find the ductility values for all 4 known Ry lines, then again to guesstimate the Ry value of the actual point. I say guesstimate because this approach only works if you make some assumptions about Ry. Foremost is that Ry changes linearly.
% Use interpolation to estimate Ry line that passes through (4,2)
% interpolate at T(s) = 4
xq=4;
yq1 = interp1(Tn,meu1,xq)
yq2 = interp1(Tn,meu2,xq)
yq4 = interp1(Tn,meu4,xq)
yq8 = interp1(Tn,meu8,xq)
% Interpolate to find Ry line at ductility = 2
yq = 2;
Ryq = interp1([yq1 yq2 yq4 yq8],[1 2 4 8],yq)
Ryq =
1.8997
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Interpolation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!