Reading the matrix elements row wise

Let say I have a matrix A = [1 2 3; 4 5 6], I can access its elements by writing A(1) and A(2) etc. but this index runs column wise. How to access elements of matrix row by row, for example if I write A(2), I want to get 2 and not 4.

Answer 1

[Paul Hoffrichter]

If you do not want to take the transpose of the A matrix, you can work with the subscripts instead.

A = [1 2 3; 4 5 6];
sz = size(A);
fiA = @(x) sub2ind(sz, ceil( x/sz(2) ), rem(x-1, sz(2)) + 1);

xx = 1:numel(A);
A(fiA(xx))
ans =
     1     2     3     4     5     6

[Paul Hoffrichter]

To test with another matrix:

B = [1 2 3; 4 5 6; 10 20 30; 40 50 60; 70 80 90];
sz = size(B);
fiB = @(x) sub2ind(sz, ceil( x/sz(2) ), rem(x-1, sz(2)) + 1);
yy = 1:numel(B);
B(fiB(yy))
ans =
  Columns 1 through 8
     1     2     3     4     5     6    10    20
  Columns 9 through 15
    30    40    50    60    70    80    90
A(fiA(5))
ans =
     5
B(fiB(10))
ans =
    40

[Salahuddin Tariq]

Thanks for updating the other methods :) because I was aware that how to do it using the transponse matrix operation. Actually I wanted to avoid the usage of for loop while scanning the elements of matrix.

Answer 2

[Paul Hoffrichter]

A = [1 2 3; 4 5 6];
Atr = transpose(A);
Atr(1:6)
ans =
     1     2     3     4     5     6