To Write a function called voltage that computes the voltages at different junctions in electrical circuit. after writing the program the output is not coming please help

16 Ansichten (letzte 30 Tage)
function sol = voltage(V,R)
M =[R(2)*R(7)+R(1)*R(2)+R(1)*R(7),-R(1)*R(2),0;-R(3)*R(4)*R(8),R(4)*R(7)*R(8)+R(3)*R(4)*R(8)+R(3)*R(4)*R(7)+R(3)*R(7)*R(8),-R(3)*R(4)*R(7);0,-R(5)*R(6),R(6)*R(8)+R(5)*R(6)+R(5)*R(8)];
y =V*[R(2)*R(7);R(4)*R(7)*R(8);R(6)*R(8)];
SOL=M\y;
end

Antworten (5)

Ritvij Sahasrabuddhe
Ritvij Sahasrabuddhe am 2 Jan. 2021
You have used 'sol' and 'SOL' as function def output, which are considered 2 different variables

PRASANTH R
PRASANTH R am 27 Dez. 2020

Anthony
Anthony am 1 Mär. 2021
Bearbeitet: DGM am 4 Mär. 2023
function sol = voltage(V,R)
M =[R(2)*R(7)+R(1)*R(2)+R(1)*R(7),-R(1)*R(2),0;
-R(3)*R(4)*R(8),R(4)*R(7)*R(8)+R(3)*R(4)*R(8)+R(3)*R(4)*R(7)+R(3)*R(7)*R(8),-R(3)*R(4)*R(7);
0,-R(5)*R(6),R(6)*R(8)+R(5)*R(6)+R(5)*R(8)];
y =V*[R(2)*R(7);R(4)*R(7)*R(8);R(6)*R(8)];
sol=M\y;
end

Tapan Chahar
Tapan Chahar am 15 Mai 2022
Bearbeitet: DGM am 4 Mär. 2023
function [X]=voltage(V,R)
% Writing equations about the 3 node points using Kirchoffs Law & rewritting
% them in terms of matrix we get
if R(1)==0||R(3)==0||R(5)==0
% When resistor R1 =0
if R(1)==0
A=[(1/R(3)+1/R(7)+1/R(8)+1/R(4)),(-1/R(8)) ; (-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[(V/R(3)+V/R(7));V/R(5)];
XX=A\b;
X=[V;XX];
end
% When resistor R3 =0
if R(3)==0
A=[(1/R(1)+1/R(2)+1/R(7)),0 ; (-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[(V/R(1)+V/R(7));V/R(5)];
XX=A\b;
X=[XX(1);V;XX(2)];
end
% When resistor R5 =0
if R(5)==0
A=[(1/R(1)+1/R(2)+1/R(7)),(-1/R(7)) ; (-1/R(7)),(1/R(3)+1/R(4)+1/R(7)+1/R(8))];
b=[V/R(1);V/R(3)+V/R(8)];
XX=A\b;
X=[XX;V];
end
% When both resistor R3 & R5 are =0
if R(3)==0&R(5)==0
A=[(1/R(1)+1/R(2)+1/R(7))];
b=[V/R(1)+V/R(7)];
XX=A\b;
X=[XX;V;V];
end
% When both resistor R1 & R3 are =0
if R(1)==0&R(3)==0
A=[(1/R(5)+1/R(6)+1/R(8))];
b=[V/R(5)+V/R(8)];
XX=A\b;
X=[V;V;XX];
end
% When both resistor R1 & R5 are =0
if R(1)==0&R(5)==0
A=[(1/R(3)+1/R(4)+1/R(7)+1/R(8))];
b=[V/R(3)+V/R(7)+V/R(8)];
XX=A\b;
X=[V;XX;V];
end
% When resistor R1, R3 & R5 are =0
if R(1)==0&R(3)==0&R(5)==0
X=[V;V;V];
end
% When resistor R1,R3 & R5 are non zero
else
A=[(1/R(1)+1/R(2)+1/R(7)),(-1/R(7)),0 ; (-1/R(7)),(1/R(3)+1/R(7)+1/R(8)+1/R(4)),(-1/R(8)) ; 0,(-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[V/R(1);V/R(3);V/R(5)];
X=A\b;
end
end

Tapan Chahar
Tapan Chahar am 15 Mai 2022
function X = voltage(V,R)
A = [ R(2)*R(7) + R(1)*R(2) + R(1)*R(7), -R(1)*R(2), 0;
-R(3)*R(4)*R(8), R(4)*R(7)*R(8) + R(3)*R(4)*R(8) + R(3)*R(4)*R(7) + R(3)*R(7)*R(8), -R(3)*R(4)*R(7);
0, -R(5)*R(6), R(6)*R(8) + R(5)*R(6) + R(5)*R(8) ];
b = V * [R(2)*R(7); R(4)*R(7)*R(8); R(6)*R(8)];
X = A \ b;
end

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