Which method to use, basic for loop or loop through values of a vector

5 Ansichten (letzte 30 Tage)
Vector ind has indices I want to loop through, x has values.
ind = [1 3 5];
x = [10 20 30 40 50 60 70];
ind_len = size(ind,2)
Approach 1: When using a for loop, should I use the basic incremental for loop, where I access each element of x with index values from ind vector
for i = 1:ind_len
x(ind(i))
end
Approach 2: Don't use ind_len length variable and assign ind vector to for loop
for i = ind
x(i)
end
Which method is efficient ?

Akzeptierte Antwort

Jan
Jan am 24 Dez. 2020
x = rand(1, 1e6);
y = zeros(size(x));
ind = randperm(numel(x));
tic
for loop = 1:10
for k = 1:numel(ind)
y(ind(k)) = x(ind(k));
end
end
toc
tic
for loop = 1:10
for k = ind
y(k) = x(k);
end
end
toc
% Elapsed time is 0.395765 seconds.
% Elapsed time is 0.739708 seconds.
The first approach can be handled more efficiently.

Weitere Antworten (1)

KALYAN ACHARJYA
KALYAN ACHARJYA am 24 Dez. 2020
Bearbeitet: KALYAN ACHARJYA am 24 Dez. 2020
More simpler, without loop
x(ind)
More, How to measure the performance of the code, link
The 2nd approach (If I must have to choose one from above)
  2 Kommentare
Thrisha R
Thrisha R am 24 Dez. 2020
Thank you for your time, I agree with your answer in printing it as such. But I intend to do other operation other than printing.
I measured the time for each of the for loops, the first approach turned out to be faster.
Elapsed time for first approach is 0.001047 seconds.
Elapsed time for second approach is 0.001211 seconds.
KALYAN ACHARJYA
KALYAN ACHARJYA am 24 Dez. 2020
Bearbeitet: KALYAN ACHARJYA am 24 Dez. 2020
Great one, once I run the code, as given in the question..
ind = [1 3 5];
x = [10 20 30 40 50 60 70];
ind_len = size(ind,2);
tic
for i = 1:ind_len
x(ind(i));
end
toc
tic
for i = ind
x(i);
end
toc
Elapsed time is 0.000021 seconds.
Elapsed time is 0.000016 seconds.

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