fractional-order,Index exceeds the number of array elements (1)

1 Ansicht (letzte 30 Tage)
Farshid R
Farshid R am 22 Dez. 2020
Kommentiert: Farshid R am 23 Dez. 2020
Hi
Good time
I wrote this code but it gives an error
Please help me
thank you
%%
n=100;
u1=[0,0]';
X1=[-4,-2,0]';
a=0.9;
h=0.9;
cp1=1;cp2=1;cp3=1;
for j=1:n
c1(j)=(1-(1+a)/j)*cp1;
c2(j)=(1-(1+a)/j)*cp2;
c3(j)=(1-(1+a)/j)*cp3;
cp1=c1(j); cp2=c2(j); cp3=c3(j);
end
% initial conditions setting:
v1(1)=u1(1);
w1(1)=u1(2);
x1(1)=X1(1); y1(1)=X1(2); z1(1)=X1(3);
% calculation of phase portraits /numerical solution/:
for i=2:n
x1(i)=h*cos(z1(i-1))*v1(i-1) - memo(x1, c1, i);
y1(i)=h*sin(z1(i-1))*v1(i-1)-memo(y1, c2, i);
z1(i)=h*w1(i-1)-memo(z1, c3, i) ;
end
%%
function [yo] = memo(r, c, k)
%
temp = 0;
for j=1:k-1
temp = temp + c(j)*r(k-j);
end
yo = temp;
%
%%%%% error
Index exceeds the number of array elements (1).
Error in exocstrstateFcnCT1 (line 28)
x1(i)=h*cos(z1(i-1))*v1(i-1) - memo(x1, c1, i);

Antworten (1)

Walter Roberson
Walter Roberson am 23 Dez. 2020
You only initialize
v1(1)=u1(1);
and you do not assign to any other entry in v1, so when i becomes 3, v1(i-1) becomes v1(2) which does not exist.
  11 Kommentare
Farshid R
Farshid R am 23 Dez. 2020
For the second part, how to code it, please help
Farshid R
Farshid R am 23 Dez. 2020
function z=myStateFunction1(x,u,X2G,X3G,k)
a=0.9;h=0.9;
cp1=1;cp2=1;cp3=1;
c1= nchoosek(a,k);
c2=nchoosek(a,k);
c3=nchoosek(a,k);
cp1=c1; cp2=c2; cp3=c3;
z(1)=x(1); z(2)=x(2); z(3)=x(3);
z(1)=h*cos(x(3))*u(1) - memo(z(1), c1, k);
z(2)=h*sin(x(3))*u(1)-memo(z(2), c2, k);
z(3)=h*u(2)-memo(z(3), c3, k) ;
%%
function [x0] = memo1(r, c, k)
temp = 0;
for j=1:k-1
temp = temp + c(j)*r(k-j);
end
x0 = temp;
Start of Error Report
------------------------------------------------------
Array indices must be positive integers or logical values.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by