Average of 3d matrix
10 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
mohamad shirgholami
am 14 Dez. 2020
Bearbeitet: KALYAN ACHARJYA
am 14 Dez. 2020
hi
I have 3D matrix with dimension (61,57,365) the 365 is daily time. I want to do a monthly average overtime to get (61,57,12). But the number of days each month is different. I would be grateful for your help
0 Kommentare
Akzeptierte Antwort
KALYAN ACHARJYA
am 14 Dez. 2020
Bearbeitet: KALYAN ACHARJYA
am 14 Dez. 2020
#One Way
m=cumsum([0,31,28,31,30,31,30,31,31,30,31,30,31]);
data=rand(61,57,365); %Sample Data
month_ave=zeros(1,12)
for i=1:12
data1=data(:,:,m(i)+1:m(i+1));
month_ave(i)=mean(data(:));
end
month_ave
7 Kommentare
KALYAN ACHARJYA
am 14 Dez. 2020
Mohmad comments moved here
hi
What do you mean by index?
if index=[31,28,31,30,31,30,31,31,30,31,30,31] , all arrays of output matrix become zeros.
thanks.
KALYAN ACHARJYA
am 14 Dez. 2020
Bearbeitet: KALYAN ACHARJYA
am 14 Dez. 2020
In this case it added 2 more loops,definitely which isn't an efficient/easiest way out.
m=cumsum([0,31,28,31,30,31,30,31,31,30,31,30,31]);
data=rand(61,57,365); %Sample Data
ave_data=zeros(61,57,12);
for r=1:61
for c=1:57
for d=1:12
data1=data(r,c,m(d)+1:m(d+1));
ave_data(r,c,d)=mean(data1(:));
end
end
end
ave_data
Weitere Antworten (1)
Walter Roberson
am 14 Dez. 2020
%Sample Data
data = rand(61,57,365);
data(:,:,200:250) = 0;
%the work
m = cumsum([0,31,28,31,30,31,30,31,31,30,31,30,31]);
month_ave = zeros(size(data,1), size(data,2), 12);
for month = 1 : 12
start_at = m(month)+1;
end_at = m(month+1);
month_ave(:,:,month) = mean(data(:,:,start_at:end_at), 3);
end
%show results
format long g
mat2str( reshape(month_ave(1,1,:),1,[]) )
Yup, the zero due to the gap I wrote into the data does show up in the result.
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!