Dear all,
I have an image and when it is read in matlab, it is [m*n] matrix, named M,
I need to create another matrix, named MM, which is exactly M, but the indexes are also listed in that.
In fact, MM has 3 columns and the third column is M (:), but the first two columns are i and j which
i=1:m, j=1:n
Thanks in advance

2 Kommentare

Trying to follow you. For this example, spell out what you want MM to be.
M =
1 2 3
4 5 6
7 8 9
10 11 12
>> M(:)
ans =
1
4
7
10
2
5
8
11
3
6
9
12
Shabnam M
Shabnam M am 11 Dez. 2020
I need also the index related to data of MM

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Ameer Hamza
Ameer Hamza am 11 Dez. 2020
Bearbeitet: Ameer Hamza am 11 Dez. 2020

0 Stimmen

You can use meshgrid() like this
[r,c] = ndgrid(1:size(M,1), 1:size(M,2));
MM = [r(:), c(:), M(:)];

6 Kommentare

Shabnam M
Shabnam M am 11 Dez. 2020
Bearbeitet: Shabnam M am 11 Dez. 2020
Thanks for your kind reply,
Actually I checked your proposal but seems sth is wrong and could not correctly create MM, could you recommend another way?
Rik
Rik am 11 Dez. 2020
What error did you get? Or is the result not what you wanted? If so, how is it different?
Shabnam M
Shabnam M am 11 Dez. 2020
the results are not right, I compared them with raw data and the data are different
Shabnam M
Shabnam M am 11 Dez. 2020
The size of r and c are (n*m), but M is (m*n) and that may create the difference?
Rik
Rik am 11 Dez. 2020
Bearbeitet: Rik am 11 Dez. 2020
The cause of this inconsistency is that Matlab stores arrays in a column-major form. So if you want to use (:) to transform an array into a vector, you need to make sure the result of your coordinate grid matches that order.
The solution is simple: replace meshgrid by ndgrid. Each of these functions has their use, but ndgrid will give the required order in this case. (you could also sort r and c, but that would be an unnecessary operation)
Ameer Hamza
Ameer Hamza am 11 Dez. 2020
Yes, ndgrid is more appropriate here. I have edited the answer.

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