how to convert a 16-bit or 64-bit signed floting point to binary
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
masters~ now I'm facing a problem that i have to convert some signed floating point numbers to binary, like -4.182068393394077e-04, or 1.3489.
do anybody have some idea or advices?
thanks
5 Kommentare
Walter Roberson
am 28 Mär. 2013
I have never encountered an unsigned floating point representation. I have encountered unsigned fixed point representations.
The closest you could get to -4.4367e-04 with a signed floating point representation would be to use a scheme with 1 sign bit, 5 exponent bits, 1 "hidden bit", and 10 bits of mantissa. That would allow you to express -(836/1024 + 1) / 2^12, or approximately -4.4346E-04. Notice this only gives you a few decimal places.
5 digits of accuracy requires 16 or 17 bits and the bits for the exponent. 1 sign bit, 5 bits of exponent, 1 hidden bit, 15 bits of mantissa = 21 bits of representation.
Antworten (2)
Walter Roberson
am 28 Mär. 2013
dec2bin(typecast(TheNumber, 'uint16'), 16) - '0'
16 Kommentare
Walter Roberson
am 31 Mär. 2013
You need binary for the channel encoder. That is
dec2bin(typecast(TheNumber, 'uint16'), 16) - '0'
You can reshape() that to vector form. Just be sure to reshape() it back before using bin2dec() to convert the binary to numeric form.
Jan
am 28 Mär. 2013
What exactly is a "binary stream"? It could be a vector of doubles, which contains only ones and zeros. Of a vector of type LOGICAL, or UINT8. Or remember, that all numbers are stored in binary format on a computer, so perhaps this is enough already:
x = pi;
x_bin = typecast(x, 'uint8')
Siehe auch
Kategorien
Mehr zu Convert Image Type finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!